SOLUTION
To obtain the maximum value that she will jump, we will
1. Differentiate the given function
2. Equate it to 0, and obtain a value for x
3. Substitute the value of x back into the intial function and obtain what f(x) will be. The value that we obtain will be the maximum value.
Step 1:
[tex]\begin{gathered} f(x)=-5x^2+10x+15 \\ \frac{df}{dx}=2(-5)x^{2-1}+1(10)x^{1-1}+0 \\ =-10x^1+10x^0 \\ =-10x+10 \end{gathered}[/tex]Step 2:
[tex]\begin{gathered} \frac{df}{dx}=0 \\ -10x+10=0 \\ -10x=-10 \\ x=\frac{-10}{-10} \\ x=1 \end{gathered}[/tex]Step3:
[tex]\begin{gathered} f(x)=-5x^2+10x+15 \\ substitutIng\text{ x=1 into f(x), we will obtain the maximum value} \\ f(1)=-5(1)^2+10(1)+15 \\ f(1)=-5+10+15 \\ f(1)=20 \end{gathered}[/tex]Therefore the highest(maximum) point that Jane will reach in the air is 20feet.