Line AB with endpoints A(4,4) and B(5,-1) is reflected in the line y=x to create its image Line A’B’. Graph A’B’. Then, find the perimeter of the figure formed by the segments Line AB , Line B’B and Line AB’ to the nearest tenth. The grey line was already graphed for me already. I started by graphing the points 4,4 and 5,-1. Then I reflected it in the line y=x but I’m having trouble figuring out the perimeter.

Line AB with endpoints A44 and B51 is reflected in the line yx to create its image Line AB Graph AB Then find the perimeter of the figure formed by the segments class=

Respuesta :

• Given the line AB whose endpoints are:

[tex]\begin{gathered} A\mleft(4,4\mright) \\ B\mleft(5,-1\mright) \end{gathered}[/tex]

You know that the line of reflection is:

[tex]y=x[/tex]

By definition, the rule for that Reflection is:

[tex](x,y)\rightarrow\mleft(y,x\mright)[/tex]

Then, the endpoints of the Image A'B' are:

[tex]\begin{gathered} A(4,4)\rightarrow A^{\prime}(4,4) \\ B(5,-1)\rightarrow B^{\prime}(-1,5) \end{gathered}[/tex]

Therefore, you can notice that the lines of AB and A'B' are graphed correctly.

• According to the information given in the exercise, you must find the perimeter of the figure formed by these segments:

[tex]\begin{gathered} AB \\ B^{\prime}B \\ AB^{\prime} \end{gathered}[/tex]

Look at the following picture, where you can see the segments that form a triangle:

You can see in the picture a triangle that is formed by the segments AB, B’B and AB'.

To find the length of each segment by using the formula for calculating the distance between two points:

[tex]d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Where the points are:

[tex](x_1,y_1);(x_2,y_2)_{}[/tex]

Therefore, knowing the endpoints of each segment of the triangle, you get:

- Length of the side AB:

[tex]AB=\sqrt[]{(5-4)^2+(-1-4)^2}[/tex][tex]\begin{gathered} AB=\sqrt[]{(1)^2+(-5)^2} \\ AB=\sqrt[]{26} \end{gathered}[/tex]

- Length of the side AB':

[tex]A^{}B^{\prime}=\sqrt[]{(-1-4)^2+(5-4)^2}=\sqrt[]{26}[/tex]

- Length of the side B'B:

[tex]B^{\prime}B=\sqrt[]{(-1-5)^2+(5-(-1))^2}=6\sqrt[]{2}[/tex]

Knowing the length of each side, you can add them in order to find the perimeter:

[tex]P=\sqrt[]{26}+\sqrt[]{26}+6\sqrt[]{2}\approx18.7\text{ }units[/tex]

Therefore, the answer is:

[tex]P\approx18.7\text{ }units[/tex]

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