Question

If a bullet leaves the muzzle of a rifle with a speed of 600 m/s, and the barrel of the rifle is 0.800 m long, at what rate is the bullet accelerated while in the barrel?That is the question I'm struggling with ^^Here are the letters that I usea= accelerationx= distancet= timeVi= Initial VelocityVf= Final Velocity

Answer 1

Given that the final velocity of the bullet is

$V_f=600\text{ m/s}$

The initial velocity of the bullet is

$V_i=\text{ 0 m/s}$

The distance traveled by the bullet is x = 0.8 m

We have to find the acceleration.

Let the acceleration be denoted by a.

The equation required to calculate acceleration is

$(V_f)^2-(V_i)^2=2ax$

Substituting the values, the acceleration will be

$\begin{gathered} (600)^2-(0)^2=2a\times0.8 \\ a=\frac{360000}{1.6} \\ =225000m/s^2 \end{gathered}$

Thus, the acceleration is 225000 m/s^2.