Given:
The tuition at a college is increasing by 5.6% each year
Let the tuition = a
So, the increases every year will form a geometric sequence
The first term = a
And the common ratio = r = 1.056
And the general term will be:
[tex]a_n=a\cdot r^{n-1}[/tex]We will find the value of (n) at the term (2a)
[tex]\begin{gathered} 2a=a\cdot1.056^{n-1}\rightarrow(\div a) \\ 2=1.056^{n-1} \end{gathered}[/tex]Taking the natural logarithm to both sides
[tex]\begin{gathered} \ln 2=(n-1)\cdot\ln 1.056 \\ n-1=\frac{\ln 2}{\ln 1.056}\approx12.72 \\ n=12.72+1=13.72 \end{gathered}[/tex]so, the tuition will be double after 13 years