Question

Question 12 only, I inserted a picture. Please show your work. graph the solution to the in equality

Answer 1

From the problem, we have :

$x^2<16$

Note that if the inequality symbol is <, the solution is is the form :

$awhere b is greater than a.

Solve for x :

[tex]\begin{gathered} x^2<16 \\ \sqrt[]{x^2}<\sqrt[]{16} \\ x<\pm4 \end{gathered}$

So we have two values of x, -4 and 4. Using the format above, 4 is greater than -4.

The solution will be :

[tex]-4Note also that if the inequality symbol is < or >, the endpoints are open circles.

Graph the solution :