Question

What is the percent increase in tuition to the nearest tenth of a percent

Answer 1

a Percentage of increasing = [(New - Original)/original] x 100%

Since the original is 10500

Since the new is 11300

Then (New - original) = 11300 - 10500 = 800

Then substitute them in the rule above

$\begin{gathered} I=\frac{800}{10500}\times100 \\ I=\frac{8}{105}\times100 \\ I=7.62 \end{gathered}$

The increasing percentage is 7.62% to the nearest tenth of percent