[tex]C)\:\frac{15}{17}[/tex]
1) As we can see, this is a right triangle. So, we can tell that the sine of angle A is:
[tex]\begin{gathered} \sin(A)=\frac{opposite\;leg\:to\:angle\:A}{hypotenuse} \\ \\ \sin(A)=\frac{30}{34}\:\:Simplify\:it \\ \\ \sin(A)=\frac{15}{17} \end{gathered}[/tex]
Note that we need to simplify that whenever possible. Thus, the answer is :
[tex]\frac{15}{17}[/tex]
