Step 1
Given; The following table shows the breakdown of opinions for both faculty and students in a recent survey about the new restructuring of the campus to include an Honors College. Find the probability that a randomly selected person is either neutral or in favor of the restructuring Express your answer as a fraction in the lowest terms or a decimal rounded to the nearest millionth.
Step 2
[tex]\begin{gathered} P(neutral)=\frac{46}{201} \\ P(favour)=\frac{83}{201} \end{gathered}[/tex]
Thus;
[tex]\frac{46}{201}+\frac{83}{201}=\frac{43}{67}=0.641791[/tex]
Answer;
[tex][/tex]