Given:
[tex]f(x)=x^2-8x+12[/tex]Required:
To find the critical value of the given function.
Explanation:
Consider the given function,
[tex]f(x)=x^2-8x+12[/tex]Calculate the derivative of the given function.
[tex]f^{\prime}(x)=2x-8[/tex]Solve f'(x)=0,
[tex]\begin{gathered} 2x-8=0 \\ \\ 2x=8 \\ \\ x=\frac{8}{2} \\ \\ x=4 \end{gathered}[/tex]Therefore, the critical value is at 4.
Final Answer:
Critical value of the given function is 4.
