How much air, to the nearest tenth of a cubic inch, is being held by a spherical balloon with a diameter of 12 inches?

Given that the diameter of the spherical balloon is = 12 inches.
So, the radius of the balloon will be = d/2 = 12/2 inches = 6 inches
Now the volume of the sphere is given as V
[tex]V=\frac{4}{3}\pi r^3[/tex]So the required volume will be
[tex]\begin{gathered} V=\frac{4}{3}\times\frac{22}{7}\times6\times6\times6\text{ cubic inches} \\ V=\frac{4\times22\times2\times6\times6}{7}\text{ cubic inches} \\ V=\frac{6336}{7}\text{ cubic inches = 905.14 cubic inches} \end{gathered}[/tex]After roundoff to the nearest tenth answer will be 905.10 cubic inches.
Hence, 905.10 cubic inches of air was held by the balloon