Answer:
[tex]232.14\text{ grams}[/tex]
Explanation:
Here, we want to get the mass of manganese chloride
We start by getting the number of moles of HCl
Mathematically:
[tex]number\text{ of moles = }\frac{mass}{molar\text{ mass}}\text{ = }\frac{22.42}{36.46}\text{ = 0.615 mol}[/tex]
From the information given, 1 mole of Hcl produces 3 moles of MnCl2
Thus, the number of moles of MnCl2 produced will be:
[tex]0.615\text{ }\times\text{ 3 = 1.84 mol}[/tex]
Finally, to get the mass, we multiply the above number of moles by the molar mass of MnCl2
Mathematically, we have that as:
[tex]1.84\text{ }\times\text{ 125.84 = 232.14 grams}[/tex]
