The equation of a line perpendicular to y is
[tex]y=-7x+b[/tex]where b is a constant hitherto unknown.
However, we also know that this perpendicular line passes through (-3,2); therefore, the above equation must satisfy y(-3) = 2.
Putting x = -3 into the above equation gives us
[tex]y(-3)=-7(-3)+b=2[/tex][tex]21+b=2[/tex][tex]\therefore b=-19[/tex]Hence, the equation perpendicular to y = 1/7x-3 which passes through (-3, 2) is
[tex]\textcolor{#FF7968}{y=-7x-19}\text{\textcolor{#FF7968}{.}}[/tex]
