Given:
[tex]f(x)=4(3x-5)[/tex]Required:
[tex]f^{-1}(x)[/tex]Solution:
First, set y = 4 ( 3x - 5), then solve for x in terms of y
[tex]\begin{gathered} y=4(3x-5) \\ y=12x-20 \\ y-20=12x \\ 12x=y-20 \\ \frac{12x}{12}=\frac{y-20}{12} \\ x=\frac{y-20}{12} \end{gathered}[/tex]Lastly, write the answer using x as a variable
[tex]f^{-1}(x)=\frac{x-20}{12}[/tex]Answer:
[tex]f^{-1}(x)=\frac{x-20}{12}[/tex]