Answer:
K'(-3, 6)
Explanation:
From the graph, the coordinates of G, H, and K are: G(1,3), H(6,0), and K(6,3).
If a point (x,y) is rotated 90 degrees counterclockwise about the origin, the transformation rule is:
[tex](x,y)\to(-y,x)[/tex]
Thus, the coordinates of the image points of the triangle GHK are:
[tex]\begin{gathered} G(1,3)\to G^{\prime}(-3,1) \\ H(6,0)\to H^{\prime}(0,6) \\ K(6,3)\to K^{\prime}(-3,6) \end{gathered}[/tex]
The coordinates of the image of the point K is (-3,6).
