Given,
The force acting on the mass m is F.
The acceleration of mass m is a.
The force acting on the mass 20m is 10F.
From Newton's second law,
[tex]F=ma[/tex]
Therefore,
[tex]10F=10(ma)\text{ }\rightarrow\text{ (i)}[/tex]
From Newton's second law, the force acting on the mass 20m is given by,
[tex]10F=20m\times a_0\text{ }\rightarrow\text{ (ii)}[/tex]
Where a₀ is the acceleration of the mass 20m
On substituting the equation (i) in equation (ii),
[tex]\begin{gathered} 10\times ma=20m\times a_0 \\ \Rightarrow a_0=\frac{10\times ma}{20m} \\ =\frac{a}{2} \end{gathered}[/tex]
Thus the resulting equation is a/2.
Therefore, the correct answer is option A.
