Question

Pb(SO4)2 + 4 LiNO3 -- Pb(NO3)4 + 2 Li2SO4How many moles of LiNO3 are needed to produce 52 grams of Lithium sulfate?

Answer 1

Answer:

0.946moles

Explanations:

Given the balanced chemical reaction shown below;

$Pb(SO_4)_2+4LiNO_3\rightarrow Pb(NO_3)_4+2Li_2SO_4$

Given the following parameter

Mass of Lithium sulfate = 52 grams

Determine the moles of Lithium sulfate

$\begin{gathered} moles\text{ of }Li_2SO_4=\frac{mass}{molar\text{ mass}} \\ moles\text{ of }Li_2SO_4=\frac{52}{109.94} \\ moles\text{ of }Li_2SO_4=0.473moles \end{gathered}$

According to stoichiometry, 4moles of LiNO3 produces 2 moles of Lithium sulfate, the moles of LiNO3 required to produce this amount is given as;

$\begin{gathered} moles\text{ of LiNO}_3=\frac{4moles\text{ of LiNO}_3}{2moles\text{ of Li}_2SO_4}\times0.473moles\text{ }Li_2SO_4 \\ moles\text{ of LiNO}_3=0.946moles \end{gathered}$

Hence the moles of LiNO3 are needed to produce 52 grams of Lithium sulfate is 0.946moles