b = number of boxes of crayons Ms Cohen buys
Let:
M = amount of money you she spend
She wants to buy boxes of crayons that cost $2 per box. She also buys a poster for $5. Ms. So:
[tex]2b+5[/tex]Since she can spend at most $30:
[tex]2b+5\le30[/tex][tex]\begin{gathered} \text{Solve for b:} \\ \text{subtract 5 from both sides:} \\ 2b+5-5\le30-5 \\ 2b\le25 \\ \text{divide both sides by 5} \\ \frac{2b}{2}\le\frac{25}{2} \\ b\le12.5 \\ \text{ to the nearest whole:} \\ b\le12 \end{gathered}[/tex]she can buy at most 12 boxes of crayons