Question

A pedestrian walks at rate of 6km per an hour east. The wind pushes him northeast at a rate of 13 km per hour. Find the direction of the resultant vector

Answer 1

Answer:

$R=14.32km.hr^{-1}$

Explanation: We have to find the resultant velocity of the pedestrian, the sketch of the scenario is as follows:

The resulting rate is as follows:

$\begin{gathered} R=\sqrt{x^2+y^2} \\ R=\sqrt{6^2+13^2} \\ R=\sqrt{205} \\ R=14.32km\text{ /hr} \end{gathered}$