[tex]speed:\text{ 231}\frac{ft}{s}[/tex][tex]Distance\text{ fallen in 10 seconds: 2310 ft}[/tex]
Explanation
to solve this we need to know the equivalence, in this case it is
[tex]1\text{ m=3.3 ft}[/tex]
then, we can make a equivalent fraction, this fraction needs to have the unit to convert in the denominator, for this problem the unit to convert is the meter, so
[tex]\begin{gathered} \frac{3.3\text{ ft}}{1\text{ m}}\Rightarrow equivalent\text{ fraction} \\ note\text{ that } \\ \frac{3.3\text{ft}}{1\text{m}}=1,\text{ so the amount is not changed} \end{gathered}[/tex]
hence
Step 1
convert from yards per second into ft per second, to do that, just multiply by the equivalent fraction
so
[tex]\begin{gathered} 70\frac{m}{s} \\ 70\frac{m}{s}*\frac{3.3ft}{1\text{ m}}=231\frac{ft}{s} \end{gathered}[/tex]
so, the speed is
[tex]speed:\text{ 231}\frac{ft}{s}[/tex]
Step 2
now, to find the distance we need to mutltiply the speed for the time,so
[tex]distance=\text{ speed *time}[/tex]
replace
[tex]\begin{gathered} distance=231\frac{ft}{s}*10\text{ s} \\ distance=2310\text{ ft} \end{gathered}[/tex]
so
[tex]Distance\text{ fallen in 10 seconds: 2310 ft}[/tex]
I hope this helps you