Respuesta :

Recall that in polar coordinates:

[tex](r,\theta)=(-r,\theta+\pi)\text{.}[/tex]

1) Notice that:

[tex]\frac{11\pi}{6}=\frac{5\pi+6\pi}{6}=\frac{5\pi}{6}+\pi[/tex]

2) Using the first equation we get:

[tex](1,\frac{5\pi}{6})=(-1,\frac{5\pi}{6}+\pi)=(-1,\frac{11\pi}{6})\text{.}[/tex]

Answer: -1.

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