Step 1
Given;
[tex]\begin{gathered} 3x+4y=-3---(1) \\ 5x+3y=6---(2) \end{gathered}[/tex]Required; To find the system of equations.
Step 2
[tex]\begin{gathered} From\text{ equation 1; } \\ 3x=-3-4y \\ x=\frac{-3-4y}{3} \end{gathered}[/tex][tex]\begin{gathered} Substitute\text{ in equation 2} \\ 5(\frac{-3-4y}{3})+3y=6 \\ 5(-3-4y)+9y=18 \\ \end{gathered}[/tex][tex]\begin{gathered} -15-20y+9y=18 \\ -11y=18+15 \\ y=\frac{33}{-11} \\ y=-3 \end{gathered}[/tex]Step 3
Find the value of x
[tex]\begin{gathered} x=\frac{-3-4y}{3} \\ x=\frac{-3-4(-3)}{3} \\ x=\frac{9}{3}=3 \end{gathered}[/tex]Answer;
[tex]x=3,y=-3[/tex]