Answer:
Explanation:
Given the point (3, -7)
Sketching this, we have:
Only cosine is positive in this quadrant, so we have:
[tex]\begin{gathered} \sin\theta=-\frac{7}{\sqrt{58}} \\ \\ \cos\theta=\frac{3}{\sqrt{58}} \\ \\ \tan\theta=-\frac{7}{3} \end{gathered}[/tex]