Question

Ohm’s law states that the current (I) in amps equals the voltage (E) in volts divided by the resistance (R) in ohms. If you connected a 2 megohm resistor (2 × 106 ohms) across a 2.4 kilovolt voltage source (2.4 × 103 volts), what would be the current in amps?Choice 'A'1.02 × 10-3 ampsChoice 'B'1.2 × 10-3 ampsChoice 'C'1.2 × 103 ampsChoice 'D'10.2 × 10-3 amps

Answer 1

Ohm’s law states that the current (I) in amps equals the voltage (E) in volts divided by the resistance (R) in ohms.

That is,

$I=\frac{E}{R}$

It is given that,

$Resistor,R=2\times10^6\text{ ohms}$$voltage,E=2.4\times10^3\text{ volts}$

Hence, current I is,

$\begin{gathered} I=\frac{2.4\times10^3}{2\times10^6} \\ I=1.2\times10^3\times10^{-6} \\ I=1.2\times10^{-3}\text{amps} \end{gathered}$

Hence, the correct option is option B.

That is,

$1.2\times10^{-3}amps$