Question

1 of 1-lQuestion 3 of 10Find the holes of the functionA. x = -3, x = -2B. noneC. x = -3, x = -2, x = 0-2x (x+3)²(x+2)3x(x+2)(x+3)²

Answer 1

Given:

There are given the function:

$f(x)=\frac{-2x(x+3)^2(x+2)}{3x(x+2)(x+3)^2}$

Explanation:

Find the holes in the graph by factoring and canceling.

So,

The holes are;

$x=0,-2,-3$

Final answer:

Hence, the correct option is C.