Question

(36-3i) - (12+24i)simplify the expression and then classify the result as a real number or imaginary number. If the result is an imaginary number, specify if it is a pure imaginary number.

Answer 1

The given complex plane is,

$z=\mleft(36-3i\mright)-(12+24i)$

Now, simplifying the given complex plane,

$\begin{gathered} z=(36-3i)-(12+24i) \\ z=36-3i-12-24i \\ z=24-27i \end{gathered}$

Hence, 24 is the real number and -27 is the imaginary number.

The pure imaginary number is the number that is only the product of a real number and the imaginary number.

Here -27 which is a real number is multiplied by the imaginary number y.

Therefore, the purely imaginary number is -27i