Question

What is the length of the hypotenuse? If necessary round to the nearest 10th

Answer 1

The pythagorean theorem tell us:

$\text{hyppotenuse}^2=\text{leg1}^2_{}+\text{leg2}^2$

The legs in this case are:

leg1 = 63mm

leg2 = 16mm

Thus:

$c^2=(63mm)^2+(16mm)^2$

And now we can solve:

$\begin{gathered} c=\sqrt[]{(63mm)^2+(16mm)^2} \\ c=\sqrt[]{3969mm^2+256mm^2} \\ c=\sqrt[]{4225mm^2} \\ c=65mm \end{gathered}$

The lenght of the hyppotenuse is 65mm