Question

Question 4 of 10The reference angle foris the terminal point ofO A. (1,³)2√√32OB.O c. (-3,-¹)O D. (¹1)is, which has a terminal point of?(³₁1).22What

Answer 1

Given:

$The\text{ terminal point of }\frac{\pi}{6}\text{ is \lparen}\frac{\sqrt{3}}{2},\frac{1}{2}).$$The\text{ referenc angle for }\frac{7\pi}{6}\text{ is }\frac{\pi}{6}.$

Required:

$\text{ We need to find the terminal point of }\frac{7\pi}{6}.$

Explanation:

$cos(\frac{\pi}{6})=\frac{\sqrt{3}}{2}\text{ and }sin(\frac{\pi}{6})=\frac{1}{2}$$cos(\frac{7\pi}{6})=cos(\pi+\frac{\pi}{6})=-cos(\frac{\pi}{6})=-\frac{\sqrt{3}}{2}$$sin(\frac{7\pi}{6})=sin(\pi+\frac{\pi}{6})=-sin(\frac{\pi}{6})=-\frac{1}{2}$

Final answer:

$The\text{ terminal point of }\frac{7\pi}{6}\text{ is \lparen}\frac{-\sqrt{3}}{2},\frac{-1}{2}).$