EXPLANATION
Challenger cost = $14,000
Car depreciaton = 11%/yr = 0.11 (in decimal form)
A) The function that represents the value of David's car V(t) is the following:
[tex]y=a(1-r)^t[/tex]
Where y= value as a function of t, a= initial amount and r is the rate of depreciation.
Replacing terms:
[tex]V(t)=14,000(1-0.11)^t[/tex]
B) Now, we can graph the function by drawing some points:
C) The car's value after 6 year would be given by pluggin in t=6 into the function:
[tex]V(6)=14000(1-0.11)^6[/tex]
Computing the power:
[tex]V_{(6)}=14,000(0.89)^6=14,000\cdot0.496=6957[/tex]
The value of the car after 6 years would be $6957.