Given:
[tex]f(x)=\frac{3x+1}{x^{2}-4}[/tex]
To find the discontinuity point:
As we know,
Any point at which a function fails to be continuous is called a discontinuity.
Set the denominator equal to zero.
We get,
[tex]\begin{gathered} x^2-4=0 \\ x^2=4 \\ x=\pm2 \end{gathered}[/tex]
Hence, the function is discontinued at points -2 and 2.
Thus, the answers are -2 and 2.
