Question

Hello! Would like some help on this one, thank you!

Answer 1

Given:

Distance = 130 meters

θ = 35 degrees

F = 40 N

Let's find the work done if the traveler moves 130 meters.

Let's first make a free body sketch:

To find the work done by the traveler over the 130 meters, we have:

$W=(Fcos\theta)x$

Where:

• W is the work done

,

• F is the force applied

,

• θ is the angle.

,

• x is the distance

Thus, we have:

$\begin{gathered} W=(40cos35)*130 \\ \\ W=32.766*130 \\ \\ W=4259.59\approx4260\text{ Nm} \end{gathered}$

Therefore, the work done is 4260 Nm.

• ANSWER:

4260 Nm.