In a circle, the perpendicular bisector of a chord contains the center of the circle.Given : O X with L the 1 bisector of WY.Prove: L contains the center of O X.

All radii of the circle are congruent.Therefore, the radii XW and XY are congruent
[tex]\begin{gathered} XW\cong XY \\ \end{gathered}[/tex]