We can see that the right triangle is:
since its a right triangle, we can apply Pytagoras theorem:
[tex]50^2+50^2=c^2[/tex]hence, we have
[tex]\begin{gathered} c=\sqrt[]{50^2+50^2} \\ c=\sqrt[]{2\cdot50^2} \\ c=50\sqrt[]{2} \end{gathered}[/tex]Now, the length of fence is the perimeter P of the triangle:
[tex]P=50+50+c[/tex]by substituying c into the last equation, we have
[tex]\begin{gathered} P=50+50+\sqrt[]{2}50 \\ P=50(1+1+\sqrt[]{2}) \\ P=50(2+\sqrt[]{2}) \end{gathered}[/tex]or
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