Question

Read each problem carefully. Solve each quadratic equation for the variable(s) specified. Be sure to show all of your work. Explain in two to three sentences what the meof the solution(s) are in relation to the problem situation.2. The product of two negative consecutive numbers is 210. The equation to represent this is: n(n + 1) = 210. Solve for n.

Answer 1

Given:

$n(n+1)=210$

Sol:.

$\begin{gathered} n(n+1)=210 \\ n^2+n=210 \\ n^2+n-210=0 \end{gathered}$$\begin{gathered} n^2+n-210=0 \\ n^2+15n-14n-210=0 \\ n(n+15)-14(n+15)=0 \\ (n+15)(n-14)=0 \\ n=-15,14 \end{gathered}$

The product of two negative number that mean number is negative.

$\begin{gathered} n=-15 \\ \end{gathered}$

Then another number is:

$\begin{gathered} n+1=-15+1 \\ =-14 \end{gathered}$

Number is -15,-14

Product of two negative consecutive number that mean if one number is "n" then another number is "n+1" and where n is a neagtive number so the value of "n" accept only negative value.

Consecutive number is define as a alternet number if the one number is "n" then another is may be "n+1" or "n-1".