Question

A rectangle patio has a perimeter of 74 feet if the length of the patio is 2 feet less than twice the width find the dimensions of the patio

Answer 1

Given:

$\begin{gathered} Perimeter=74feet \\ length=2\times width-2feet \end{gathered}$

To Determine: The dimension of the patio

Solution

The formula for finding the perimeter of a rectangle is

$\begin{gathered} P=2(l+w) \\ Given \\ l=2w-2 \\ P=2(2w-2+w) \\ P=2(3w-2) \\ Note,P=74feet \end{gathered}$

Therefore

$\begin{gathered} 2(3w-2)=74 \\ 3w-2=\frac{74}{2} \\ 3w-2=37 \\ 3w=37+2 \\ 3w=39 \\ w=\frac{39}{3} \\ w=13feet \end{gathered}$$\begin{gathered} l=2w-2 \\ l=2(13)-2 \\ l=26-2 \\ l=24feets \end{gathered}$

Hence the dimension of the patio is 24feets by 13feets