Question

If the length of a rectangle is expressed by2x2 + 4x – 8 and the width is 3x. What is the area ofthe rectangle ?

Answer 1

$\begin{gathered} L=2x^2+4x-8 \\ w=3x \\ \text{Area}=L\times w \\ \text{Area}=(2x^2+4x-8)\times3x \\ \text{Area}=6x^3+12x^2-24x \end{gathered}$