Respuesta :

We are given the following inequality:

[tex]-6x-17\ge8x+25[/tex]

To solve for "x" we will first subtract 8x to both sides:

[tex]\begin{gathered} -6x-8x-17\ge8x-8x+25 \\ -14x-17\ge25 \end{gathered}[/tex]

Now we will add 17 to both sides:

[tex]\begin{gathered} -14x-17+17\ge25+17 \\ -14x\ge42 \end{gathered}[/tex]

Dividing both sides by -14, and since we are dividing by a negative number we will invert the direction of the inequality sign:

[tex]x\le\frac{42}{-14}[/tex]

Solving the operation:

[tex]x\le-3[/tex]

Thererfore, the solution is x <= -3

RELAXING NOICE
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