Use a geometric mean theorem or set up similar triangles to solve for the variable or find the indicated side length.All answers should be in simplified radical form:Please enter a square root as follows:2v2 as 2sqrt2 OR V2 as sqrt2

Use a geometric mean theorem or set up similar triangles to solve for the variable or find the indicated side lengthAll answers should be in simplified radical class=

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The figure for the triangle is,

Consider the triangle ABD and triangle ABC.

[tex]\begin{gathered} \angle ABD\cong\angle ABC\text{ (Common angle)} \\ \angle BAC=\angle BDA\text{ (Each right angle)} \\ \Delta ABD\approx\Delta CBA\text{ (By AA similarity)} \end{gathered}[/tex]

So triangle ABD is similar to triangle CBA. So ratio of sides of triangle are equal.

[tex]\frac{AD}{AC}=\frac{AB}{CB}=\frac{BD}{AB}[/tex]

Determine the length of AB by using the ratio of sides.

[tex]\begin{gathered} \frac{AB}{14}=\frac{6}{AB} \\ (AB)^2=84 \end{gathered}[/tex]

Consider the triangle ABD.

Determine the value of x by using the pythagoras theorem

[tex]\begin{gathered} (AB)^2=x^2+(6)^2 \\ 84=x^2+36 \\ x=\sqrt[]{84-36} \\ =\sqrt[]{48} \\ =4\sqrt[]{3} \end{gathered}[/tex]

So value of x is,

[tex]4\sqrt[]{3}[/tex]

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