Consider the following hyperbola.(x + 3)2 (y + 5)23664Step 1 of 3: Find the coordinates of the vertices of the hyperbola.AnswerHow to enter your answer (opens in new window)Vertices:

Given the hyperbola:
[tex]\frac{(x+3)^2}{36}-\frac{(y+5)^2}{64}=1[/tex]Where:
(h,k) is the center
First, we know that this hyperbola is horizontal since the x term is first. Therefore, the center is (-3, -5) and a = 6, b = 8.
This way you can also find the vertices: (h ± a, k). Therefore, the vertices are:
(-3 + 6, -5) = (3, -5)
(-3 - 6, -5) = (-9, -5)
Answer: (3, -5) and