Question

A star with a mass of 3.72 x 1030 kilograms and a radius of 8.67 x 108 meters rotates on its axis once every 32 days. A star is a solid sphere, which has a k value of 2/5. What is the angular momentum of the star? Include units in your answer. Answer must be in 3 significant digits.

Answer 1

Given:

Mass of star, m = 3.72 x 10³⁰ kg

Radius, R = 8.67 x 10⁸ meters

Number of days, T = 32 days

k = 2/5

Let's find the angular momentum of the star.

To find the angular momentum of the star, apply the formula:

$L=kmR^2\times\frac{2\pi}{T}$

Where:

T is the time in seconds = 60 * 60 *24 * 32 days =2764800 seconds

Thus, we have:

$\begin{gathered} L=(\frac{2}{5}\times3.72\times10^{30})\times(8.67\times10^8)^2\times\frac{2\pi}{2764800}^{} \\ \\ L=2.54\times10^{42}kg/m^2\text{ /sec} \end{gathered}$

ANSWER:

$2.54\times10^{42}kg/m^2\text{ /sec}$