Question

Which of the following values of x solves 6^2x-1=36^-x41/3-41/4

Answer 1

ANSWER

x = 1/4

EXPLANATION

$\begin{gathered} 6^{2x-1}=36^{-x} \\ 6^{2x-1}=6^{2(-x)} \\ 6^{2x-1}=6^{-2x} \\ \text{Equate the power of 6} \\ 2x\text{ - 1 = -2x} \\ 2x\text{ + 2x = 1} \\ 4x\text{ = 1} \\ x\text{ = }\frac{1}{4} \end{gathered}$