Question

A parallel plate capacitor has plate separation of 4.0 cm and a plate area of 4.0x10-2 m2. What is the capacitance of this capacitor?Group of answer choices8.9x10^-12 F8.9x10^-13 F8.9x10^-15 F8.9x10^-14 F

Answer 1

In order to calculate the capacitance of this capacitor, we can use the formula below:

$C=\frac{\epsilon_0A}{d}$

Where C is the capacitance (in Farad), e0 is the dielectric constant (equal to 8.9 * 10^-12) A is the plate area (in m²) and d is the plate separation (in m).

So, for A = 4 * 10^-2 m² and d = 0.04 (equal to 4 * 10^-2) m, we have:

$\begin{gathered} C=\frac{8.9\cdot10^{-12}\cdot4\cdot10^{-2}}{4\cdot10^{-2}} \\ C=8.9\cdot10^{-12}\text{ F} \end{gathered}$

Therefore the correct option is the first one.