Question

varies directly sqrt(x) and inversely as y ^ 2; z = 147 when x = 49 and y = 8 find x = 64 and y = 2 (Round off your answer to the nearest hundredth)

Answer 1

Explanation:

we are given the following statement:

According to this statement, z varies directly as √x and varies inversely as y^2. This means that there is a constant c such that:

$z=c\frac{\sqrt{x}}{y^2}$

now, if z = 147 when x = 49 and y = 8, we get:

$147=c\frac{\sqrt{49}}{8^2}$

solving for the constant c, we get:

$c=\frac{(8^)^2147}{\sqrt{49}}=1344$

thus, we get the following final equation:

$z=1344\frac{\sqrt{x}}{y^2}$

thus, if x = 64 and y = 2, we get that z is:

$z=1344\frac{\sqrt{64}}{2^2}=2688$

we can conclude that the correct answer is:

Answer:

2688