i inserted a picture of question 8 & 9 they both go together, the value of a from question 7 is 45=a(30)(30-60)

7. We need to solve the equation to find the a-value. The equation is:
[tex]\begin{gathered} 45=a(30)(30-60) \\ 45=a(30)(-30) \\ 45=a(-900) \\ a=\frac{45}{-900} \\ a=-0.05 \end{gathered}[/tex]8. a=-0.05, r1=0 and r2=60.
Then the equation is:
[tex]\begin{gathered} y=-0.05(x-0)(x-60) \\ y=-0.05(x)(x-60) \end{gathered}[/tex]9. Using the distributive property, we obtain the following equation:
[tex]\begin{gathered} y=-0.05\cdot(x\cdot x-x\cdot60) \\ y=-0.05(x^2-60x) \\ y=-0.05\cdot x^2-0.05\cdot(-60x) \\ y=-0.05x^2+3x \end{gathered}[/tex]This is the quadratic form of the equation.