The function is:
[tex]h(x)=x^2+3x-18[/tex]When completing the square, we take half of coefficient of 3, square it up and add it to the constant and rearrange. THe process shown below:
[tex]\begin{gathered} h(x)=x^2+3x-18 \\ h(x)=(x+\frac{3}{2})^2-18-(\frac{3}{2})^2 \\ h(x)=(x+\frac{3}{2})^2-18-\frac{9}{4} \\ h(x)=(x+\frac{3}{2})^2-\frac{81}{4} \end{gathered}[/tex]So, this is the form after completing the square.
