The question is given to be:
[tex]5\left(x-8\right)=7\left(x-4\right)[/tex]Step 1: Expand the parentheses using the distributive property given to be
[tex]a\lparen b-c)=a\cdot b-a\cdot c[/tex]Thus, we have:
[tex]5x-40=7x-28[/tex]Step 2: Subtract 5x from both sides
[tex]\begin{gathered} 5x-40-5x=7x-28-5x \\ -40=2x-28 \end{gathered}[/tex]Step 3: Add 28 to both sides
[tex]\begin{gathered} -40+28=2x \\ -12=28 \end{gathered}[/tex]Step 4: Divide both sides by 2
