The general vertex form of a quadratic equation is:
[tex]y=a(x-h)^2+k[/tex]where the point (h,k) is the vertex
In the case of
[tex]y=2(x-3)^2-2[/tex]the vertex is located at (3,-2). Also, we can see that a = 2, which is greater than 0, this means that the curve opens up