We have the following:
1.
the formula for the slope is:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
The points are (-5, 4) and (5, - 2)
replacing:
[tex]m=\frac{-2-4}{5-(-5)}=\frac{-6}{5+5}=-\frac{6}{10}=-\frac{3}{5}[/tex]
The y-intercept (b) is 1, the equation of a line in slope intercept form is:
[tex]y=mx+b[/tex]
replacing:
[tex]y=-\frac{3}{5}x+1[/tex]
2.
The points are (- 1, - 3) and (1, 3)
replacing
[tex]m=\frac{3-(-3)}{1-(-1)}=\frac{3+3}{1+1}=\frac{6}{2}=3[/tex]
The y-intercept (b) is 0, replacing:
[tex]y=3x[/tex]
