Question

Factor each polynomial using the difference of two perfect squares

Answer 1

Number 5

So for the difference of perfect squares factor with the numbers on both factors having to be the same, but one adds and one subtracts.

$m^2-\frac{1}{9}$$\begin{gathered} \text{The formula is} \\ a^2-b^2=(a+b)(a-b)_{} \end{gathered}$

$m^2-\frac{1}{9}=(m+\frac{1}{3})(m-\frac{1}{3})$