write the perimeter of the triangle as a simplified expression y+64y-22yt1

Given the triangle;
The perimeter of a shape is the sum of the sides or outer parts of the shape.
Thus, the perimeter of the triangle is;
[tex]y+6+4y-2+2y+1[/tex]Then, we simplify further by collect like terms, we have;
[tex]\begin{gathered} y+4y+2y+6-2+1 \\ =7y+5 \end{gathered}[/tex]