Given:
The initial temperature of the silver is
[tex]T_i=\text{ 10}^{\circ}\text{ C}[/tex]The final temperature of the silver is
[tex]T_f=\text{ 90}^{\circ}\text{ C}[/tex]The heat added is Q = 1 kcal = 1000 cal
The specific heat of silver is
[tex]\text{C}_{silver}\text{ = 0.056 cal/g }^{\circ}C[/tex]Required: The mass of the silver.
Explanation:
The mass of the silver can be calculated by the formula
[tex]\begin{gathered} Q=mC(T_f-T_i) \\ m=\frac{Q}{C(T_f-T_i)} \end{gathered}[/tex]On substituting the values, the mass will be
[tex]\begin{gathered} m=\frac{1000}{0.056\times(90-10)} \\ =223.21\text{ g} \end{gathered}[/tex]Final Answer: The mass of the silver is 223.31 g